caller-dirname

Get the directory name of a caller function's containing file.

---

$3

``bash
$ npm i caller-dirname
`

$3

/home/detrohutt/test/caller-dirname/callee.js

`javascript
import { callerDirname } from 'caller-dirname';

export default () => callerDirname();
`

/home/detrohutt/test/caller-dirname/deeper/caller.js

`javascript
import thisDirname from '../callee.js';

console.log(thisDirname()); / /home/detrohutt/test/caller-dirname/deeper /
`

$3

| Option | Default | Description |
| ------ | ------- | --------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------- |
| depth | 1 | Depth sets the position in the call stack at which you want to retrieve the directory name. With the default depth of 1 (1st caller) you get the dirname of the function that directly calls callerDirname() (we'll call it fn1). With a depth of 2 (2nd caller), you'd instead get the dirname of the function that _called_ fn1, etc. |

##### Example

`javascript
import { callerDirname } from 'caller-dirname';

export const thirdCallerDir = () => callerDirname({ depth: 3 });
``

$3

I needed this for another repo I'm working on. Most of the code is taken from caller-path. The main difference is this returns the dirname only, rather than the full path with filename and extension. Also, it's published both as a CommonJS module and as an ES Module and includes TypeScript typings.