lazy-from (Lazy.from)

Tired of .filter().map() allocating two whole arrays every time you
chain them?
Tired of needing to convert all your iterables to an Array (with Array.from or spread syntax)
just to use map, filter, concat, flat, includes, etc?

Use Lazy.from. It's just like Array.from but no conversion to arrays
and more features (zip, toSet, take, etc).

``JavaScript Lazy.from([1,2,3]) .map(x => x*3) .filter(x => x%2==0) .map(x =>${x}) .concat([10, 11]) .concat({ [Symbol.iterator]() { yield 2; yield "hello"; }})``

- no dependencies (I might add an optional dependency of some typescript type helpers)
- written in TypeScript with well-cared-for types. Might add a version that doesn't require typescript@^4.0
- feel free to contribute fixes and new useful methods
- written using anonymous generator objects in JavaScript which make the codebase tiny and neat, check them out

lazy-from (Lazy.from)

Use Lazy.from. It's just like Array.from but no conversion to arrays
and more features (zip, toSet, take, etc).

``JavaScript Lazy.from([1,2,3]) .map(x => x*3) .filter(x => x%2==0) .map(x =>${x}) .concat([10, 11]) .concat({ [Symbol.iterator]() { yield 2; yield "hello"; }})``