TypeScript List<T>

Problem List<T> solves

Using the filter method of an Array<T> , in TypeScript, don't allow for additional parameters to be passed in and used as part of the filter condition.
List<T> solves this problem by providing a where method. This where method do allow for additional parameters to be passed in and used as part of the filter.
All standard Array<T> properties and methods are available on List<T>.

General Use

Define interface for <T>
``typescript
interface Item { name: string };
`

Create List<T>
`typescript
let list = new List();
`

Create and Add data to List<T>
`typescript
let itemOne: Item = { name: "Name1" };
let itemTwo: Item = { name: "Name2" };
list.push(itemOne);
list.push(itemTwo);
`

Define filter (T, ...arg):boolean
`typescript
let filter = (item: Item, name: string) => item.name === name;
`

Filter List<T> using where(filter, value)
`typescript
let newList = list.where(filter, "Name1");
`

Development

$3

Below command only required for development.
`
npm install
npm run setup
`

$3

After running below gulp task a html codecoverage report is made available in directory ./analysis/coverage/lcov-report.
`
gulp test
`

$3

After running below gulp task two reports are made available in directory ./analysis/complexity.
The HTML version is located in the report subdirectory.

`
gulp analyse
``
Note: complexity analysis is just experimental